Pages

Visitor

free counter

D.O.B


I made this widget at MyFlashFetish.com.

Wednesday, June 16, 2010

Tugasan 2

Part 1
(a) Ok, this is about history of probability and its applications. There are tonnes of internet web page discussing about this topic, so I think this shouldn't be any problem to you all, right?

(b) This is about theoretical and empirical probability. There are also tonnes of discussion in internet. So, just Google it. Basically, theoretical knowledge means knowledge that you obtain through your thinking, while empirical knowledge is knowledge obtain through your experience and experiments.

Part 2
(a) {1,2,3,4,5,6}
(b)

Chart


Table
Tree Diagram

Total Outcome
{ (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}

Part 3
(a)


(b)
A = { (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}

B = ø

P = Both number are prime
P = {(2,2), (2,3), (2,5), (3,3), (3,5), (5,3), (5,5)}



Q = Difference of 2 number is odd
Q = { (1,2), (1,4), (1,6), (2,1), (2,3), (2,5), (3,2), (3,4), (3,6), (4,1), (4,3), (4,5), (5,2), (5,4), (5,6), (6,1), (6,3), (6,5) }

C = P U Q
C = {1,2), (1,4), (1,6), (2,1), (2,2), (2,3), (2,5), (3,2), (3,3), (3,4), (3,6), (4,1), (4,3), (4,5), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,3), (6,5) }

R = The sum of 2 numbers are even
R = {(1,1), (1,3), (1,5), (2,2), (2,4), (2,6), (3,1), (3,3), (3,5), (4,2), (4,4), (4,6), (5,1), (5,3), (5,5), (6,2(, (6,4), (6,6)}

D = P ∩ R
D = {(2,2), (3,3), (3,5), (5,3), (5,5)}

Part 4 (a)
In this case, you need to toss dice and record your result in the table. Just in case you don't have dice at home, you can use these digital dice to do your experiment.

http://www-cs-students.stanford.edu/~nick/settlers/
http://leepoint.net/notes-java/examples ... ldice.html

The following are the sample data. You should do your experiment and collect your own data. Everybody should have different set of data.


From the table,


(i)
(ii)

(iii)
Part 5
(a)

Question:
Based on Table 1, determine the actual mean, the variance and the standard deviation of the sum of all dots on the turned-up faces by using the formulae given.
(b)

Question:
Compare the mean, variance and standard deviation obtained in Part 4 and Part 5. What can you say about the values? Explain in your own words your interpretation and your understanding of the values that you have obtained and relate your answers to the Theoretical and Empirical Probabilities.

Table below shows the comparison of mean, variance and standard deviation of part 4 and part 5
We can see that, the mean, variance and standard deviation that we obtained through experiment in part 4 are different but close to the theoretical value in part 5.

For mean, when the number of trial increased from n=50 to n=100, its value get closer (from 6.58 to 6.91) to the the theoretical value. This is in accordance to the Law of Large Number. We will discuss Law of Large Number in next section.

Nevertheless, the empirical variance and empirical standard deviation that we obtained i part 4 get further from the theoretical value in part 5. This violate the Law of Large Number. This is probably due to

The sample (n=100) is not large enough to see the change of value of mean, variance and standard deviation.
Law of Large Number is not an absolute law. Violation of this law is still possible though the probability is relative low.

In conclusion, the empirical mean, variance and standard deviation can be different from the theoretical value. When the number of trial (number of sample) getting bigger, the empirical value should get closer to the theoretical value. However, violation of this rule is still possible, especially when the number of trial (or sample) is not large enough.

Part 5 (c)

Question:
If n is the number of times two dice are tossed simultaneously, what is the range of mean of the sum of all dots on the turned-up faces as n changes? Make your conjecture and support your conjecture.

The range of the mean
Conjecture: As the number of toss, n, increases, the mean will get closer to 7. 7 is the theoretical mean.

Image below support this conjecture where we can see that, after 500 toss, the empirical mean become very close to the theoretical mean, which is 3.5. (Take note that this is experiment of tossing 1 die, but not 2 dice as what we do in our experiment)

Tugasan 3

Part1 (a)




Demand of the computer decreases as its selling price increases. In other word, the higher the selling price, the lower the quantity demand.

Part 1 (b)
Profit per unit of computer = s - 50

Total yearly profit,
Y = (s - 50) x d

Y = Total yearly profit
s = Selling Price
d = demand



From the graph in Part 1 (a), we can see that there is a linear relationship the demand and the selling price. Therefore, we can use a straight line equation to represent this relationship.

First of all, let's find the gradient and the y-intercept of the graph




Then let's form the linear equation of the graph






Substitute this into the equation of yearly profit




Y = Yearly profit
s = selling price

Part 1 (c)
Finding the maximum yearly profit

Method 1: By using calculus




Y is maximum (or minimum) when dY/ds = 0



Therefore, yearly profit Y is maximum when the selling price s = 175.

This implies that when the selling price for the computer is RM175 per unit, the company will have the maximum profit potential.

Method 2: Completing the square
We can also find the maximum profit by using the completing the square method.


Maximum profit, Y = RM312,500 when
s-175 = 0
s=175

When the selling price s = RM175, the profit is maximum.

Part 1 (d)
The number of computer,

d = -20s + 6000

For maximum profit, s = RM175

d = -20(175) + 6000
d = 2500 unit.

The number of the computer components to be manufactured by the company in order to gain maximum profit,
d = 2,500 units

Part 2 (a)
Total amount of interest incurred for each choice of repayment period and their corresponding amount of loan is as follow:


Part 2 (b)(maybe this is wrong)
The average interest rate per month is as follow:


Since the interest rate is constant over time, hence the average interest per month remain the same every month. The average interest per month is also directly proportional to the amount of loan.

Correction
A user point out that this question ask for the average interest rate per month but not the average interest per month. If this is the case, then the table should look like below:


Comment: The interest rate is the same for any term of loan and it's affected by the amount of loan. This interest rate (24% per annum) is too high for a normal bank loan

Part 2 (c)
The amount of yearly repayment for each choice of repayment period up to 5 years for loan amounts from RM10 000 to RM100 000 is as follow: This table result also have some wrong
For total annual payment for 12 months, the payment are

12408, 18600, 24804, 31008, 37200, 43404, 49608 .....

T2 - T1 = 18600 - 12400 = 6192
T3 - T2 = 24804 - 18600 = 6204
T4 - T3 = 31008 - 24804 = 6204
T5 - T4 = 37200 - 31008 = 6192
T6 - T5 = 43404 - 37200 = 6204
T7 - T6 = 49608 - 43404 = 6204


Part 2 (d)(i)
The company allocated 20% of the profit made on loan repayment.



From the table above, we find that, if the company allocate RM40,000 for loan repayment, the amount of loan it can take for repayment period, 1, 2, 3, 4, and 5 year are as follow:

Part 2 (e)



The amount of the reserve fund at the end of each month until 31St December 2010 is as follow:
This table have some problem.that is the last 3 result

Tugasan 4

Part 1(a)
Question:Collect pictures, newspaper cuttings or photos on items that you have chosen. Design a collage to illustrate the chosen items.

Part 1(b)
Question:
Record the items and their prices systematically as in Table 1. Since items may be differently packed, be sure to use consistent measurements for each item selected so that comparison can be done easily and accurately.





Question:
(c) Create at least two suitable graphical representations (the use of ICT is encouraged) to compare and contrast the prices of the items chosen.

Draw the graph or chart by using Powerpoint, Word or Excel.

Question:
(d) Based on the graphical representations that you have constructed in Part 1(c), interpret, discuss and draw conclusions. Comments on your findings.

Comment on your graph

Question:
(e) Identify an item that has a large price difference among the shops. Calculate the mean and the standard deviation of that particular item. Hence, suggest and discuss possible reasons for the price difference

From the table above, the item that has large price difference is Dynamo Regular (3kg) Detergent.

The mean of the price,



The standard Deviation = 2.60

The price difference is possibly due to Jaya Jusco and Econsave are doing promotion for this item.


PART 2(a)
Question:
Suggest a shop from Part 1 from which you would go to purchase the ingredients for the butter cakes. State and discuss your reasons for purchasing from the shop you suggested

I will purchase from Tesco because all the ingredient is the cheapest.

Part 2(b(i)

Question:
Complete Table 2 with the prices of the items found in the shop/supermarket that you have chosen.
(i) Calculate the price index for each of the ingredients in Table 2 for the year 2010 based on the year 2009.




Part 2 (b)(ii)

Question:
Calculate the composite index for making a butter cake in the year 2010 based on the year 2009. Discuss how you obtained your answers





Part 2 (b)(iii)

Question:
In the year 2009, the butter cake was sold at RM15.00 each. Suggest a suitable selling price for the butter cake in the year 2010. Give reasons for your answer




From the composite index, we know that the cost of the ingredient has risen by 25.54%. Therefore, the price of a butter cake should be adjusted upward by 25.54% (From RM15 to RM18.80) so that we can keep our profit margin unchanged

Par 2 (c) (i)

Question:
Find out from reliable sources how to determine suitable capacity of air-conditioner to be installed based on volume/size of a room.

Capacity of any cooling machine is known in 'ton'.Ton here means One ton of water(1,000kg).If we take water which alreadycool at 0 degree centigrade and switch on the machine, then quantity of ice produced in 24 hours(one day) will determine its capacity.If it produces one ton of ice then capacity of machine is one ton.If it produces 100 kg of ice(solid) in 24 hrs then the capacity is 0.1 ton.

To determine the BTUs needed to cool a given space follow this procedure:


Calculate the total square feet to be cooled: Measure the size of the room (or rooms) to be cooled, to obtain total square feet. Multiply room length by width for each room and if there are multiple rooms, add the room areas together to get a single number.
Read the Base BTUs needed from Table below.The table below gives recommended air conditioning BTU's necessary to cool a single room. The data in the table assumes that the ceiling over the room is insulated and that the room is not over or is not itself a special heat-producing area such as a kitchen or boiler room.

Add additional BTUs for these factors:

+ 4,000 BTUs for each room below a ceiling or roof which is not insulated
+ 4,000 BTUs for a home or residential kitchen included in the cooled area
+ 1,500 BTUs for each window which receives significant daily sunshine
+ 1,500 BTUs for a room over a kitchen or boiler room IF the kitchen or boiler room is actively producing heat during the cooling period
+ 600 BTUs per person over two, if more than two occupants will be occupying the room during the cooling period
Subtract BTUs from the total required if these factors are present:

- 1,000 BTUs if the room is on the shaded side of the building
Calculate the final total BTUh needed from the above steps. This should place you in the right range of cooling capacity needed. Review the warning below about buying an oversized air conditioner.


Question:
(ii) Work in groups to estimate the volume of your school library. Explain how you arrive at your answer. Hence, determine the number of air conditioners with the appropriate capacity required for your library.

(iii) If your class intends to sponsor one air conditioner for the school library, how many butter cakes must your class sell in order to buy the air conditioner?


For this part, you have to do it by yourself.

(Source of information: http://sawaal.ibibo.com/physics/how-cal ... 13215.html)
(Source of information: http://www.inspectapedia.com/aircond/Ai ... rChart.htm)

Monday, June 14, 2010

黑缘1

我是一位未满十八但将要十八岁的男生,愿望是要在中五毕业前找到第一女朋友...

自从第一次告白失败的几个月后,就在我生日后隔天,我照常去接些无聊的站岗消磨时间...

那一天是一个风和日丽的星期六,我还有我学校的两位上司都有去那.只不过是其中一位上司,我,还有一位从另外一间分队来的女生一起站岗..我还是依旧冷酷地不出声...我上司见况,就拉我去结交那位女生... 我被她那灿烂的笑容给吸引住了... 她名字起初我不会念读成 我打电动药的名字-ETHER
她教了我几次我才慢慢学会叫她名字...余啊(>.<)
我慢慢习惯回怎样与人沟通也是她的出现吧...不然我可能还是那冷血无情的人吧..那一天我就认识了第一位外校的女性朋友,当然在那站岗里我也认识到CHING,ANDREA & KAR YEE她的姐妹们... 在解散时我上司竟然对我说他喜欢上她了..我也只好把她让给他吧,他又有钱又有才华她肯定会喜欢他吧...23/06/2007


继续

Saturday, June 12, 2010

Cat Love Me



无论是黑猫,白猫,还是熊猫

都喜欢我

它们有着一双尖尖的耳朵

厚厚的肉掌使它能在高楼掉下来时让压力分散

成了它有九条命的传说

我喜欢猫叫出喵喵声的时候,因为我会同情它们

然后喂它们吃东西

它们的夜间视力会变得更好,放变于捕食老鼠



医生猫

某天的一个下午,一只医生猫与一位黑猫散步,

突然当黑猫过马路时,给车给撞晕了,医生猫便在那做出人工呼吸的知识去救它同伴

真是令人敬佩和感动



潜水猫

有一只好玩的猫,竟然跑进它们猫的死穴-水 洗衣机里

然后它主人互动洗衣机,当洗衣机停后,主人才发现它,但它竟然大命不死

只是吊盐水几小时而已



跟踪猫

有一天我回家时,看见有只小小小猫在怜叫,我就把我的饼干给了它,过了马路,我回头一望

那只小猫竟然想过马路,我继续走回家,到了家里.我竟然听见那把声音,它在走廊上徘徊喵喵叫



睡猫(CAT NAP)

CAT NAP是小息或睡午觉

猫也会睡午觉?是的它们也会,因为有一天我与朋友回家时看见的

Saturday, June 5, 2010

Sea-green zion' hairstreak 碧绿的天堂里的花蝶


  这天我经过家附近的湖泊,我把我书包丢在一旁然后躺在那一片绿油油的草地上,我望着那无边无际的蓝蓝天空,看见云朵在飘动中,突然有一只不知何时飞来的花蝶把我的目光转移到它身上了.




  我随着它走,不知不觉我已在森林里了,当我回过神时那花蝶已不见了...只见有位身穿着碧绿衣装的姑娘躺在地上...当我向前时她慢慢地站起来了,我问她还好吗,她却什么也没回答,就转身离去了,我也去找回家的路了...




  由于我是摄影组的,所以我天天都忙着帮朋友拍照与洗相片.这天奇怪的时发生了...我与我朋友的合照都有拍到那青衣女子...但我问其他朋友时,他们都说没看到我所说的女子..我去了办公室,去翻查学生个人资料,但还是没有线索...




  隔天早上,当我抵达学校时,我看见她进了我班还坐了我座位望着窗外...当我想骂她时,她回过头来对我说:"我的名叫..."由于上课铃声响起,我听不见她名字...


我是一个喜欢安静的人,所以我喜欢坐在靠窗口的位子望着窗外的景色发呆...但这天不同了..


第一天...

我坐在她旁边上课...她什么也没带也不抄笔记.但老师却不像平常一样骂没带书来的人..

下课了我当然是像饿狼一样冲去买食物吃啦...我看那女的应该连钱都没带的,于是我买了三文治给她,但她一口都不吃...

放学了...我去我的摄影学会底片室,内她跟着我,她什么也不说,只在那边看照片...


第二天

我终于看见她笑了..原来她在找我拍下的作品-(蓝色的蝴蝶) 


那蝴蝶很独特所以我拍下做纪念了.


她很喜欢那张照片,于是我给了她


第三天


她哭了,我安慰她,并问她为什么哭.她说那张照片不见了...


找了很久也找不到..我只好一直去找那种蝴蝶拍给她.


第四天
我去到了当时拍到那蝴蝶的草原去找给她


我拍了很多张那类似的蝴蝶...


但她都说不是..


第五天


今天她的脸色很差,也没有说些什么,只比平常安静..


第六天


她今天没来上课...我打算明天去找她..


第七天


她依然没来上课...


放学后我想找她但却不知她住在哪里...我想了想


我跑去我们第一次相遇的湖泊哪儿,可能她就住在哪儿附近吧...


我到了那,她坐在树阴下,我跑上前去问她为什么没去学校,她说在找他..


但他死了...她说...我抱着她说我会在她身边的,她推开了我,说那是不可能的事...我不知何时回到家了...


第八天


她还是没来学校...


我只好坐回我位子继续上课


放学后我进了底片室,我看见桌面上摆着很多我的照片,在那些照片里都有着一只绿色花蝶..到最后一张照片...就是那一张她所寻找的蓝色蝴蝶的照片,只是这张照片里多了一只绿色花蝶,我顿时才知到她就是那一只绿色花蝶


我才懂我们是不可能在一起的...祝你与他能在天堂里快乐生活.





Thursday, June 3, 2010

THE YARD YEW天井边的紫杉

今天是她的生日,但我却拿不起勇气对她说声生日快乐,
我还记得四年前的四月十三号我终于认识到她
因为那一天当我上着MORAL节时她与她朋友找我开保健室给她们休息,
她们在里面吃我们露营所剩的饼干与黄色的杯子....
我听见她与她朋友的对话,说道她姐姐前几年毕业...
我们就彼此认识了对方

可能我是个超级大笨蛋吧,我才认识她三天,就想她表白了..
可能我不该听鸡翼所教的方法-写信示爱,因为他是(爱情"专家")
当然,她拒绝了我...也想尽办法闭开我...
她托她朋友对我说我并不是她所喜欢的类型,也托她朋友传一封信给我,说她有男朋友了.
过了几天,四月17号 她身边出现了一位独中的男生 我并不喜欢与人争 所以开始放弃了...

过了一段时期,她生日要到了3/6,我朋友告诉我她喜欢SHE的新专辑 我暗中出钱与我的朋友买给她,但我不希望她知道我送的而不开心,于是我吩咐我那些朋友别告诉她此事,我不要求什么,只默默希望她开心就好...

有一天她突然流鼻血,她友找我开门,我找我伙伴去照顾她,因为我感到尴尬去面对她所以每当看到她我逃避她

我一位朋友可能要安慰我吧,他竟然拿了她成绩单里的个人照给我...
就当作留念吧...

------------------------------------------

现在的我与那时那个我已不同

我并不会再次追求你,烦着你.

我只想再次与我做朋友.

我已把你的照片归还给你了

我只希望你会对我说你还是我的朋友

我就心满意足了.

我在四年前的六月二十三号的一个DUTY认识了一位从天上派来的美妙的仙女,她改变了我的观念.我爱她但我怕她会像你一样拒绝我,所以我只好等待她的答案.

P.S:Alcohol + Carboxylic Acid + H