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Saturday, June 26, 2010

公平?

这世界真的很不公平,为什么好人总是比坏人早死呢?

为何有些人能享受荣华富贵;而有些人却衣食不足呢?



然而考获全不及格的人都可以进到大学,因为他有钱.

而那些考获全A的人却得到不公平的对待,进不了大学.



有些人有了女朋友却还一脚踏两船再私底下再追另一个

而有些人没谈过恋爱虽然喜欢那人很久了,却不能在一起



有些人有一个幸福美好的家

而有人却天天家无宁日地过



我爷爷在今年的四月离世了,我感到惭愧那天比赛完后没去见他最后一面

当我与家人在几天后想去探望他时,他已离开了

而现在我外公进了医院,我不想再有遗憾,就算有什么节目或补习,我都不去,我只去探望他



我国的大学是那么的不讲道理的吗?还是那些传闻是真的呢?他们不看成绩,只看肤色

我表哥从小学一直拿全A到中五毕业,他也刚刚从中六毕业出来

他一心想专读心理学课程,但大学却说,已经没位给他进,也说他做后补,只要有人退学,他就能进了

那课程七月就开课了,要等?真的很难啊...



我有个朋友喜欢Y小姐

Y小姐喜欢他?还有K先生

K先生已经有了朋友-C小姐 但还去追Y小姐

Y小姐也接受K先生

C小姐自动推出,成全他们

Y小姐天天都去找我朋友,吩咐他帮她做这样做那样

他一一服从她,给她利用

这段情的问题在于那里呢?Y K C 还是他?



我真的很羡慕我朋友能有个幸福的家庭

因为我并没有...

在我还没来到这不公平的世界里前,我家是很富有,有白金卡,车,楼...

我姐姐天天都有保品吃,出生时,住的房都是一间房一个人的豪房

在我诞生时,我住的也只有四人一房的中房.也没有山珍海味吃,可能物品起价吧...

过了几年后,我父亲开了一间录影社,一个月都不到,生意失败了,一夜间失去了所有东西与钱

最终被列为破产人士.他变得脾气暴燥,喝酒,抽烟,变得像豆腐渣一样烂...



我的生活并不简单,也很辛苦,小时候一直被他拿物品来敲打头,当做错事时,不但如此,当我在打电动时,不听他讲的,啪一声,我又被打了...

每一年的生日,我都过得不开心,年年如此地吵闹....
记得六年级时的生日礼物是一架数码相机,但在我毕业旅行前几天,他又喝醉,还弄不见它...所以我并没有留下快乐的照片...我妈也托他所赐,开始抽烟了

上了中学,唉由于国语不及格,就读预备班一年,我变得很静,很冷酷,不爱说话了...
上了中一最后一班,但我不放弃,因为只要考到第一,我妈就戒烟了,我考到了,但她依然还抽着...
我考进了中二第二班,我还不能放弃...我想超越我姐姐,PMR-4A....
我身边的朋友,越来越多已找到他们的"另一半"但我却还是单身汉...
我看中了一为女生,我表白了,但被拒绝了...
可能我没钱又不帅吧也很冷酷吧...
当年老头卖了车,买了五架电话,但当天吵一吵他就拿了四架电话去喝酒,然后被打劫,全没了.只剩一架
到了我那一年的生日2007年.我家老头说在KIMBALI帮我庆祝生日,那一天是星期五,我姐姐中五有补习,他说过会载她一起庆祝的,但他又喝醉酒.我到了那,看到姐姐不在,那臭老头拿了我电话,我又拿了我姐姐电话,所以我跑去找我姐姐了,我一直打给她朋友,问她们知不知到我姐姐在哪里,最后我回家了,我姐姐也在家了...虽然生日会又搞扎了,但看见姐姐没事就得到安慰,即使被她骂了一顿也罢..


隔天23-06-2007,我出外站岗了,这一天的开始改变了我的人生,因为认识了她...
我在黑暗中找寻到那一到光-希望
我终于不再冷酷下去了...于是我获得很多朋友的支持与爱戴
我又有一架电话了,但那臭老头假假说他用不惯他买的NOKIA电话...
与我交换一天,我交换了,最后的结局是被卖了...当天的回忆全没了...

在那一年,我妈又到另州出差,钱给了老头买晚饭吃,但他却一天就拿完去喝酒...
我储蓄钱很快,于是在那时候,我拿我的钱去买面包来吃....
幸好我有一个朋友阿姨是卖什饭的,我买饭才得到减价...我才不用天天吃面包

有一天那老头竟然拿工具破开我的储蓄箱,还把钱拿完去买酒喝...
幸好我还有另外一个地方藏着钱,不然就惨了.

有一天,那老头惹我,我顶撞他,他拿起PAN 想要打我(要是被他一打,我看我应该离世了)但我的潜意识觉醒了,我看见地上有条我踢爆的门里面的木条(由于有一天,我与姐姐房的门锁坏了,我用我跆拳道功力把门一脚踢飞了.里面的支撑的木条也掉落了...)我拿起来就以最快的速度打他手和一直推引他去房间,一脚踢开他,他倒在床上,手上的PAN也掉了,我拿起继续打他穿着皮鞋的脚,他也一直狂踢,因为我已爆走着...直到他喊停,我才停了下来...

PAN被我打到歪了,可想象到我打他很大力...我全身也麻痹没力了,当他走出来时,他脸肿了还流血了,可能我用木条乱打X,和那木太长了,所以打到脸了,那一夜成了我心中的阴影...

到了中三我依然保持在第二班,但因为我要打败的人SPM-7A,有点难了...
而且老头和妈也以姐为榜...我也只不过是个克星
我有过死的念头但我想起了某人对我说过的话,我放弃了自杀与离家出走的念头.
后来我搬家了,搬去AMPANG LINE PJ开始新的生活,遗憾的是,妈还是要与老头住...

它就在家不出外做工,只在家抽烟喝酒打电动..两年了...
如果是我的话肯定受不了那样的生活..我妈就在外辛苦赚钱,而它就拼命浪费钱买酒喝,
如果妈与它分开的话,可能现在的生活不会那么辛苦...

到了中四我进了第一班,但家人却没什么说,好像我一定要像姐姐一样考那么好,因为我是她弟弟...
果然中四真的不简单,全班都是一流的书生,我也只是个另类.幸好我还有外面的朋友支持,不然我已撑不下去了

到了中五我已跟他们是一伙的了...所以很快乐...
总算得到些公平的对待...

我还是与它打赌着,一天它还喝酒,我就不会原谅它

Tuesday, June 22, 2010

My 18th Birthday

Best Wish from:


  1. Amirah-wah too early to wish me la
  2. Jia Xin-you ah..
  3. Pui Yee..lol although cant be the 1st wish me,but you are form5 first to wish me.
  4. Delon-lol through face book wish me oh
  5. Kai Wei-Thanks to your voice message(Birthday song),2more days will be your birthday
  6. Andrea-lol nevermind,no need exact wish me in time
  7. Cindy-lol you be the first one in 22/6 0.00am wish me
  8. Xiao Tong-lol 0.01 delived
  9. Meng Yee-lol long time no chat
  10. Wan Rong-thanks rong
  11. Jun Wing-Oh course want people to remember my birthday la
  12. Eugene Tan-1+9+9+2+0+6+2+2=31生日
  13. Samantha-oh you will wish me oh...
  14. Mun Harn-lol didi
  15. Khai Yee-you are no 15
  16. Ah Fong-em actually I dont know who are you
  17. Weng Leiy-thanks soon onn didi
  18. Lam Kar Mun-thanks dear
  19. Karen Chew-thanks Monkey hunter
  20. Xiao Beii-em dont know who....
  21. Miow yao yong-miow
  22. Lun Zai-em
  23. Kenny Tan-kenny roger
  24. Yong Sam-thanks senpai
  25. Vincent Slillery Greene-em thanks beauty
  26. Jeff Lee-hey bro
  27. Lee Qi Wen-em..ah
  28. Chan Kar Mun-men men
  29. Tze Ling-lol while you wish me by sms i am walking to school
  30. Kee Yi-oh
  31. Cui Yuan-lol remember my present ah
  32. Wee Keat-mr gold fish
  33. Wai Yew-your wife havent wish me neh
  34. Chui Yee-my glove oh remember have南 拳these 2 words
  35. Hui Chyn-haiz,the present i gave you,how come broke so fast(T.T)
  36. Chan Wai-give me some tradisional medicine
  37. Ivan-10days before my bithday
  38. Shee Wei-lol gan ba teh for your life,and go to Adonis to wash face ba
  39. Yi Wen-lol thanks teh teh wen
  40. Nic Ma-em ah oh
  41. Mr Donald-lol teacher!belanja me!
  42. Jun Yan-sound familiar
  43. Vivian-lol Avatar wish me
  44. Rachel Wong-i am touch,cause other primary school friend in 6B also wish me
  45. Jun Jun-are you NC boy friend?
  46. Chui Li-lol ah boy
  47. Ye Pei-dadada
  48. Tan Hee Mei-GOOD
  49. Yan Ning-ok
  50. Chok Khar Shing-oh
  51. Yong Chee Yee-beautifil girl
  52. Yat Kwan-dude
  53. Xiu Xiu-bwahahaha
  54. Suk Zean-zean zean~
  55. Nicole Chan-pak tou liao la...
  56. Vincent Chang-handsome guy
  57. Yun Naam-naam wish nam
  58. Gan Ka Ye-haiz,your girl didnt wish me
  59. Men Dee-present ....loading
  60. Crystal Tao-hohoho
  61. Zhe Xin-hehehe
  62. Eric Goh-huhuhu
  63. Voon Cheng-eee...
  64. On Tao-finally
  65. Darkl Donaghy-hm...
  66. Nai Bin-your friend ah,haiz
  67. Mun Cheng-smaller than me one day
  68. Lim Wai Sang-blar blar blar
  69. Arvinder-kinder garden know each other now
  70. Kwan Wei Jin-ano?
  71. Balamy Chin-kee said your gossip
  72. Ching Yee-the prefect that i admire since primary school
  73. Wong Yuen Wen-prety girl oh
  74. Calvin Wong-belanja me drink soya lo
  75. Fei Yang-flying goat from 6B,how are you with hoo?
  76. Ong Tze Min-senpai
  77. Yung Hao Loh-er
  78. Jason Yeoh Jing Sheng-kao dao liao ma?
  79. Rachel Lim-yaya waiting for my present
  80. Yong Xin-lol at least have XIN
  81. Yee Ying-sexy babe wish me,are you ok?your injury
  82. Cheng Bee Chia-senpai
  83. Lee Yean-monkey lol
  84. Zainab Aan-how are you now?
  85. Teoh Pui Fang-???
  86. Shui Yee-em....
  87. Chen Pui Jing-6B is the best
  88. Eddy Lee-oh
  89. Puteri Nur Ain-dont sick again ah
  90. Sue Chew-哈愀!lol having flu
  91. Mr Wang Siew Hong-thans sir
  92. Nur Fairus-hihi
  93. Sook Mun-herman didi
  94. Esther Ten=alcohol + carboxylic acid + H
  95. Voon Sing-fatty boy
  96. Chen Kah Jun-ar
  97. Ming Shan-lol thanks kai ma de son
  98. Wing Lam-lol sopo wish me
  99. Yazi Wong- ...
  100. Nicole Wong-(T_T)my death note ah
  101. FORGOT-100%not Yung Kit,idiot yung kit.
  102. Ah Yeo-(-_-)same class also that late to wish
  103. Alexandria Liew-lol new friend,new wish
  104. Shiau Yin Chong-wah super belated wish

Wednesday, June 16, 2010

Tugasan 1

Reminder: This is only a guide but not the complete answer. You should try to complete the project by yourself

a) Function I



Maximum point (0,4.5) and pass through point (2,4)



b=0, c=4.5

Substitute (2,4) into (1)




Function (II)




Maximum point (0,0.5) and pass through point (2,0)





b=0, c=0.5

Substitute (2,0) into (2)





Function (III)
Maximum point (2,4.5) and pass through point (0,4)


b=2, c=4.5





Substitute (0,4) into (3)




(b)

Area of the gray region
=Area of rectangle - Area P(Green Region)





NO MORE

Tugasan 2

Part 1
(a) Ok, this is about history of probability and its applications. There are tonnes of internet web page discussing about this topic, so I think this shouldn't be any problem to you all, right?

(b) This is about theoretical and empirical probability. There are also tonnes of discussion in internet. So, just Google it. Basically, theoretical knowledge means knowledge that you obtain through your thinking, while empirical knowledge is knowledge obtain through your experience and experiments.

Part 2
(a) {1,2,3,4,5,6}
(b)

Chart


Table
Tree Diagram

Total Outcome
{ (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}

Part 3
(a)


(b)
A = { (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}

B = ø

P = Both number are prime
P = {(2,2), (2,3), (2,5), (3,3), (3,5), (5,3), (5,5)}



Q = Difference of 2 number is odd
Q = { (1,2), (1,4), (1,6), (2,1), (2,3), (2,5), (3,2), (3,4), (3,6), (4,1), (4,3), (4,5), (5,2), (5,4), (5,6), (6,1), (6,3), (6,5) }

C = P U Q
C = {1,2), (1,4), (1,6), (2,1), (2,2), (2,3), (2,5), (3,2), (3,3), (3,4), (3,6), (4,1), (4,3), (4,5), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,3), (6,5) }

R = The sum of 2 numbers are even
R = {(1,1), (1,3), (1,5), (2,2), (2,4), (2,6), (3,1), (3,3), (3,5), (4,2), (4,4), (4,6), (5,1), (5,3), (5,5), (6,2(, (6,4), (6,6)}

D = P ∩ R
D = {(2,2), (3,3), (3,5), (5,3), (5,5)}

Part 4 (a)
In this case, you need to toss dice and record your result in the table. Just in case you don't have dice at home, you can use these digital dice to do your experiment.

http://www-cs-students.stanford.edu/~nick/settlers/
http://leepoint.net/notes-java/examples ... ldice.html

The following are the sample data. You should do your experiment and collect your own data. Everybody should have different set of data.


From the table,


(i)
(ii)

(iii)
Part 5
(a)

Question:
Based on Table 1, determine the actual mean, the variance and the standard deviation of the sum of all dots on the turned-up faces by using the formulae given.
(b)

Question:
Compare the mean, variance and standard deviation obtained in Part 4 and Part 5. What can you say about the values? Explain in your own words your interpretation and your understanding of the values that you have obtained and relate your answers to the Theoretical and Empirical Probabilities.

Table below shows the comparison of mean, variance and standard deviation of part 4 and part 5
We can see that, the mean, variance and standard deviation that we obtained through experiment in part 4 are different but close to the theoretical value in part 5.

For mean, when the number of trial increased from n=50 to n=100, its value get closer (from 6.58 to 6.91) to the the theoretical value. This is in accordance to the Law of Large Number. We will discuss Law of Large Number in next section.

Nevertheless, the empirical variance and empirical standard deviation that we obtained i part 4 get further from the theoretical value in part 5. This violate the Law of Large Number. This is probably due to

The sample (n=100) is not large enough to see the change of value of mean, variance and standard deviation.
Law of Large Number is not an absolute law. Violation of this law is still possible though the probability is relative low.

In conclusion, the empirical mean, variance and standard deviation can be different from the theoretical value. When the number of trial (number of sample) getting bigger, the empirical value should get closer to the theoretical value. However, violation of this rule is still possible, especially when the number of trial (or sample) is not large enough.

Part 5 (c)

Question:
If n is the number of times two dice are tossed simultaneously, what is the range of mean of the sum of all dots on the turned-up faces as n changes? Make your conjecture and support your conjecture.

The range of the mean
Conjecture: As the number of toss, n, increases, the mean will get closer to 7. 7 is the theoretical mean.

Image below support this conjecture where we can see that, after 500 toss, the empirical mean become very close to the theoretical mean, which is 3.5. (Take note that this is experiment of tossing 1 die, but not 2 dice as what we do in our experiment)

Tugasan 3

Part1 (a)




Demand of the computer decreases as its selling price increases. In other word, the higher the selling price, the lower the quantity demand.

Part 1 (b)
Profit per unit of computer = s - 50

Total yearly profit,
Y = (s - 50) x d

Y = Total yearly profit
s = Selling Price
d = demand



From the graph in Part 1 (a), we can see that there is a linear relationship the demand and the selling price. Therefore, we can use a straight line equation to represent this relationship.

First of all, let's find the gradient and the y-intercept of the graph




Then let's form the linear equation of the graph






Substitute this into the equation of yearly profit




Y = Yearly profit
s = selling price

Part 1 (c)
Finding the maximum yearly profit

Method 1: By using calculus




Y is maximum (or minimum) when dY/ds = 0



Therefore, yearly profit Y is maximum when the selling price s = 175.

This implies that when the selling price for the computer is RM175 per unit, the company will have the maximum profit potential.

Method 2: Completing the square
We can also find the maximum profit by using the completing the square method.


Maximum profit, Y = RM312,500 when
s-175 = 0
s=175

When the selling price s = RM175, the profit is maximum.

Part 1 (d)
The number of computer,

d = -20s + 6000

For maximum profit, s = RM175

d = -20(175) + 6000
d = 2500 unit.

The number of the computer components to be manufactured by the company in order to gain maximum profit,
d = 2,500 units

Part 2 (a)
Total amount of interest incurred for each choice of repayment period and their corresponding amount of loan is as follow:


Part 2 (b)(maybe this is wrong)
The average interest rate per month is as follow:


Since the interest rate is constant over time, hence the average interest per month remain the same every month. The average interest per month is also directly proportional to the amount of loan.

Correction
A user point out that this question ask for the average interest rate per month but not the average interest per month. If this is the case, then the table should look like below:


Comment: The interest rate is the same for any term of loan and it's affected by the amount of loan. This interest rate (24% per annum) is too high for a normal bank loan

Part 2 (c)
The amount of yearly repayment for each choice of repayment period up to 5 years for loan amounts from RM10 000 to RM100 000 is as follow: This table result also have some wrong
For total annual payment for 12 months, the payment are

12408, 18600, 24804, 31008, 37200, 43404, 49608 .....

T2 - T1 = 18600 - 12400 = 6192
T3 - T2 = 24804 - 18600 = 6204
T4 - T3 = 31008 - 24804 = 6204
T5 - T4 = 37200 - 31008 = 6192
T6 - T5 = 43404 - 37200 = 6204
T7 - T6 = 49608 - 43404 = 6204


Part 2 (d)(i)
The company allocated 20% of the profit made on loan repayment.



From the table above, we find that, if the company allocate RM40,000 for loan repayment, the amount of loan it can take for repayment period, 1, 2, 3, 4, and 5 year are as follow:

Part 2 (e)



The amount of the reserve fund at the end of each month until 31St December 2010 is as follow:
This table have some problem.that is the last 3 result